A straight line L4, whose equation is 3y-2x=-2,meet the x-axis at R . Determine the cordinate of R

1 answer

To find the coordinate of point R, we need to substitute y=0 in the equation of the line L4.

The equation is 3y - 2x = -2.

Substituting y=0, we get:

3(0) - 2x = -2

0 - 2x = -2

-2x = -2

Divide both sides of the equation by -2:

x = 1

Therefore, the x-coordinate of point R is 1.

Since point R is on the x-axis, its y-coordinate is 0.

Therefore, the coordinates of point R are (1, 0).
Similar Questions
  1. a straight line passes through p(-1,1) and q(3,4)a) find the length of line pq b) find the equation of the perpendicular
    1. answers icon 1 answer
  2. the straight L has gradient 3 and passes through the point A(-6,4).a) find an equation for L in the form y=mx+c b) straight line
    1. answers icon 1 answer
  3. Line L1 has equation 2x -3y+12=0Gradient of L1 is 2/3x The line L1 crosses the x axis at the point A and the y axis at the point
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions