L1 has intercepts at A:(-6,0) and B:(0,4)
L2 has gradient -3/2 and passes through (0,4), so L2 is
y-4 = (-3/2)(x-0)
3x+2y-8 = 0
L2 passes through B:(0,4) and C:(8/3,0)
So, if you plot the points, you can see that you have a triangle with base along the x-axis, and its third point on the y-axis.
Line L1 has equation 2x -3y+12=0
Gradient of L1 is 2/3x
The line L1 crosses the x axis at the point A and the y axis at the point B.
The line L2 is perpendicular to L1 and passes through B.
A) find and equation of L2
The line L2 crosses the x axis at the point C
B) find the area of triangle ABC
Thankyou
1 answer