A stone of mass 5kg is projected with a rubber catapult. If the catapult is stretched through a distance of 7cm by the average of the force 70 N. Calculate the instateneous velocity when it is released

Answer 1

Work in = average force * distance = 70 N * 0.07 meter = 4.9 Joules
so
(1/2) m v^2 = 4.9 Joules
(1/2)(5) v^2 = 4.9

Answer 2

Its not correct pls