A stone is thrown with an initial speed of 15 m/s at an angle of 37 above the horizontal from the top of a 35 m building. If g = 9.8 m/s2 and air resistance is negligible, then what is the magnitude of the vertical velocity component of the rock as it hits the ground?

Answer 1

First calulate the time T when it hits the ground.

y = 35 + Vo sin37*T - (g/2)T^2 = 0

Solve that for time T. You know what Vo and g are. You must solve a quadratic. Take the positive root.

Get the vertical velocity component by solving
Vy (at t = T) = Vo sin 37 - g*T

It should end up being a negative number.