A stone is thrown upwards with an initial velocity of 25m /s at an angle of 30 degree to the ground then explain why the horizontal component of the stone velocity at the start is 21.7m/s?

Answer 1

The horizontal component of the stone's velocity at the start is 21.7m/s because it is determined by the initial velocity and the angle of the throw. The horizontal component of the velocity is calculated using the equation vx = v * cos(angle), where v is the initial velocity and angle is the angle of the throw. In this case, vx = 25m/s * cos(30°) = 21.7m/s.