on the ground
The horizontal velocity of the stone just before it lands on the ground will be the same as its initial horizontal velocity, which is 21.2 m/s. This can be calculated using the equation:
vx = v0 * cos(θ)
where vx is the horizontal velocity, v0 is the initial velocity, and θ is the angle of the throw. In this case, vx = 25 * cos(30) = 21.2 m/s.
A stone is thrown upwards with an initial velocity of 25m/s at an angle of 30 degree to the ground then find what will the stone horizontal velocity be just before it lands
1 answer