A stone is thrown straight down from the edge of a roof, 825 ft above the ground, at a speed of 5 ft/sec.

A. Given that the acceleration due to gravity is -32 ft/sec2, how high is the stone 2 seconds later?
751 ft.

B. At what time does the stone hit the ground?
7.02615 sec.

C. What is the velocity of the stone when it hits the ground?
___ft/sec.
I can't find C

3 answers

From your data
height = -16t^2 - 5t + 825

Agree with your a) and b) answers

v = -32t - 5
when t = 7.026 , v = -32(7.026) - 5
= ...... ft/s
I did that too and I got -299.823 but it is showing that it's wrong, idk why
I got -229.8384

since it asked for velocity, you must use the negative sign,
or else say 229.8364 ft/sec downwards or something along those lines