A stock solution has a concentration of 12.4 M. What volume of stock solution would be needed to make 7.6 L of solution with a concentration of 4.4 M?

Question

Which substance is an example of a nonpolar compound?

Which statement is the best explanation for the graph?
1. As temperature rises, the space between liquid particles decreases, leaving less room for gas particles.
2. As temperature rises, the space between liquid particles increases, allowing more room for gas particles.
3. As temperature rises, gas particles are moving faster and are more likely to enter the solution.
4. As temperature rises, gas particles are moving faster and may leave the solution.

After which action would the concentration of a solution remain constant?
evaporating water from the container
evaporating water from the container

adding water to the solution
adding water to the solution

adding solute to the solution
adding solute to the solution

removing solution from the container
removing solution from the container

Answer 1

For the dilution problem:
mLa x Ma = mLb x Mb
mLa x 12.4M = 7,600 mL x 4.4M
Solve for mLa (the stock solutioin), add that volume to a flask, add diltilled water to make a final volume of 7,600 mL, mix thoroughly, label.
The remainder of the post makes no sense. I don't see a graph either.

Answer 2

It's questions I need answered what lol

Answer 3

0.32 M
2.70 L
Vegetable oil
As temperature rises, gas particles are moving faster and may leave the solution
Evaporating the water from the container
Solutes and Solvents Quick Check answers

Answer 4

deez is right about all except the last one. the coorect answer was "removing solution from the container".