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A steel wire in a piano has a length of 0.6000 m and a mass of 3.000 10-3 kg. To what tension must this wire be stretched so th...Asked by Emily
A steel wire in a piano has a length of 0.5000 m and a mass of 3.800 10-3 kg. To what tension must this wire be stretched in order that the fundamental vibration correspond to middle C (fC = 261.6 Hz on the chromatic musical scale)?
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Answered by
Elena
λ =2L=2•0.5 = 1 m
v= λ•f=1•261.6 = 261.6 m/s
v = sqrt(T/m₀)=
=sqrt(T•L/m)
v²= T•L/m
T= v²m/L=261.6²•3.8•10⁻³/0.5=520.10 N
v= λ•f=1•261.6 = 261.6 m/s
v = sqrt(T/m₀)=
=sqrt(T•L/m)
v²= T•L/m
T= v²m/L=261.6²•3.8•10⁻³/0.5=520.10 N
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