A steel sphere of radius 6.5 mm is dropped into a lake. What is the terminal speed of the sphere?
4 answers
More information. Terminal speed in the water?
Yes, I think we are supposed to assume that it is in water.
The problem here is the assumptions of friction of a small sphere The drag equation is
force drag=densitywater*velocity^2*.47*area
you can calculate area from radius.
at terminal velocity, net force=dragforce
mg-bouyantforce=drag force
now the mass m of the steel ball can be calculated from density steel*volumesphere
bouyant force=densitywater*volumeball*g
do all that, and then you can calculate terminal velocity v of the ball in the water.
force drag=densitywater*velocity^2*.47*area
you can calculate area from radius.
at terminal velocity, net force=dragforce
mg-bouyantforce=drag force
now the mass m of the steel ball can be calculated from density steel*volumesphere
bouyant force=densitywater*volumeball*g
do all that, and then you can calculate terminal velocity v of the ball in the water.
Thanks for your help, but I think that it is wrong. I keep getting 1.13 m/s as the answer, so I don't know if I went wrong somewhere.
1 answer