No, I am not going to Google Young's modulus of steel for you, E
L = 0.6 m
r = 0.0025 m
A = pi (.0025)^2
delta L/L = 2.5(9.81)/(E A)
delta L = 0.6*2.5*9.81/(E*pi*.0025^2)
A steel rod of length 60 cm and radius 2.5 mm hangs vertically. If a mass of 2.5 kg
is attached to the end of the rod, calculate the increase in the length of the rod
1 answer