A steel rod of length 60 cm and radius 2.5 mm hangs vertically. If a mass of 2.5 kg

Question

is attached to the end of the rod, calculate the increase in the length of the rod

Answer 1

No, I am not going to Google Young's modulus of steel for you, E

L = 0.6 m
r = 0.0025 m

A = pi (.0025)^2

delta L/L = 2.5(9.81)/(E A)

delta L = 0.6*2.5*9.81/(E*pi*.0025^2)