An ideal spring hangs vertically from the ceiling. When 1.0 kg mass hangs from the spring it is extended 5.0 cm from its relaxed length. A downward external force is now applied to the mass to extend the spring an additional 10 cm. While the spring is being extended by the force, what is the work done by the spring?

1 answer

work done=finalenergy-initialenergy
= 1/2 k (.15)^2-1/2 k(.05^2)
= 1/2 k (.0225-.0025)