Coefficient expansion for copper in Celsius
1.7*10^-5/C°
A steel pipe 8.25 m long is installed at 45°C. Find the decrease in length when coolants at -60°C pass through the pipe
4 answers
Correction, for steel
1.3*10^-5/C°
1.3*10^-5/C°
That's 1.3E-5 WHAT/C. meters, cm, ? Substitute into the following:
delta L = alpha*delta T*L
You can read more about it here.
http://en.wikipedia.org/wiki/Thermal_expansion
delta L = alpha*delta T*L
You can read more about it here.
http://en.wikipedia.org/wiki/Thermal_expansion
So would this be the setup?
(1.3x10^-5/C°)(8.25m)(-105°C)=-0.01m
(1.3x10^-5/C°)(8.25m)(-105°C)=-0.01m