Use V(final)^2=V(initial)^2+2ad
62^2 = 0 + 2(a)(22)
a=87.364 m/s^2
Then use F=ma
F=(4)(87.364)
F=349.455 N (you may have to round this to get 2 sig figs)
A steel ball has a mass of 4.0kg and rolls along a smooth, level surface at 62m/s.
A) Find its kinetic energy(i got this and its 7688 joules)
B)?????-At first, the ball was at rest on the surface. A constant force acted on it through a distance of 22 meters to give it the speed of 62m/s. What was the magnitude of the force??
I really don't understand part b. please help in detail! Thxs
1 answer
1 answer