Since it is rolling you must consider both the kinetic energy of both translation (forward motion) and rotation. The rotational kinetic energy is (1/2) I w^2 where I = (2/5) M R^2 for a solid sphere, and w = V/R is the angular velocity.
Put it all together and you find that the kinetic energy is (7/10)M V^2
Divide that by the distance of 22m over which the force acted, and you get the average force.
A steel ball has a mass of 4.0 kg and rolls along a smooth, level surface at 62m/s. What is its kinetic energy. At first the ball was at rest on the surface. A force acted on it through a distance of 22 m to give it the speed of 62 m/s. What was the magnitude of the force?
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