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A star the size of our Sun runs out of nuclear fuel and, without losing mass, collapses to a white dwarf star the size of our E...Asked by clara
A star the size of our Sun runs out of nuclear fuel and, without losing mass, collapses to a white dwarf star the size of our Earth. The radius of our Sun is 6.96×108m , the radius of Earth is 6.37×106m
If the star initially rotates at the same rate as our Sun, which is once every 25 days, determine the rotation rate of the white dwarf.
If the star initially rotates at the same rate as our Sun, which is once every 25 days, determine the rotation rate of the white dwarf.
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Answered by
bobpursley
momentum is conserved
initial momentum=finalmomentum
2/5 *M*6.96E8wi=2/3*M*6.37E6*wf
wi=1rev/25days
wf=wi*(6.96E8/6.37E6)
= about 4 revs/day or 27.46rad/day
initial momentum=finalmomentum
2/5 *M*6.96E8wi=2/3*M*6.37E6*wf
wi=1rev/25days
wf=wi*(6.96E8/6.37E6)
= about 4 revs/day or 27.46rad/day
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