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A star the size of our Sun runs out of nuclear fuel and, without losing mass, collapses to a white dwarf star the size of our E...Asked by clara
A star the size of our Sun runs out of nuclear fuel and, without losing mass, collapses to a white dwarf star the size of our Earth. The radius of our Sun is 6.96×108m , the radius of Earth is 6.37×106m .
If the star initially rotates at the same rate as our Sun, which is once every 25 days, determine the rotation rate of the white dwarf.
If the star initially rotates at the same rate as our Sun, which is once every 25 days, determine the rotation rate of the white dwarf.
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Answered by
bobpursley
angular momentum remains the same.
momentinertia*w=finalmomentinertia*wf
2/5(mri^2)wi=2/5(mrf^2)wf
wf=wi*(ri/rf)^2
wf=2pi/25 *(6.96E8/6.37E6)^2 rad/day
wf=3000 rad/day or 477 rotations/day
check the math.
momentinertia*w=finalmomentinertia*wf
2/5(mri^2)wi=2/5(mrf^2)wf
wf=wi*(ri/rf)^2
wf=2pi/25 *(6.96E8/6.37E6)^2 rad/day
wf=3000 rad/day or 477 rotations/day
check the math.
Answered by
Helpful
mastering physics requires the answer to be in rad/sec so the answer ends up being .035 rad/s
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