a squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrels height above the ground. Give your answer to the nearest hundredth

Answer 1

To find the rate of change in the squirrel's height above the ground, we can divide the change in height by the change in time.

The initial height of the squirrel above the ground is 100 feet, and it moves down to a height of 45 feet above the ground. Thus, the change in height is 100 - 45 = 55 feet.

The change in time is given as 5.25 seconds.

Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds = 10.48 feet per second.

Rounded to the nearest hundredth, the rate of change in the squirrel's height above the ground is 10.48 feet/second.