The quotient to describe the rate of change in the squirrel's height above the ground is the distance traveled divided by the time taken.
The distance traveled is 100 - 45 = 55 feet.
The time taken is 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55/5.25 ≈ 10.48 feet per second.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth.
3 answers
negative or positive?
The rate of change in the squirrel's height above the ground is negative because the squirrel is moving downwards from its perch to the stored acorns.
1 answer