The quotient can be interpreted as the rate of change in the squirrel's height above the ground. To find the rate of change, we divide the change in height by the time taken.
The squirrel starts at a height of 100 feet above the ground and moves down to a height of 45 feet above the ground. The change in height is 100 - 45 = 55 feet.
The time taken is 5.25 seconds.
The rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds = 10.48 feet/second.
Therefore, the rate of change is approximately 10.48 feet/second.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground. Give your answer to the nearest hundredth.
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