A square, 0.69 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. This axis is perpendicular to the plane of the square. A force of 17.1 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque (in N*m) such that a force could produce?
3 answers
force times maximum distance from axis which is half the diagonal of the square directed perpendicular to that diagonal.
So i multiply 0.69 by ?? 0.345?
diagonal is .69 * sqrt 2
half of that is (.69/2) *sqrt 2 = .488
half of that is (.69/2) *sqrt 2 = .488
1 answer