200 N/mm = 200*10^3 Newtons/meter
so k = 2*10^5 Newtons/meter
find work to compress 0.150 meter
find work to compress 0.200 meter
difference is additional work to do last 0.050 meter
so
W = (1/2)kx^2
W = (1/2)(2*10^5)(0.20^2 - 0.15^2) Joules
A spring with a tension of 200N/mm is compressed for a distance of 150mm.
Determine the Work done if the spring is compressed a further 50mm.
2 answers
work (stored energy) is equal to ... 1/2 * k * d^2
calculate work for 150 mm and 200 mm ... find the difference
calculate work for 150 mm and 200 mm ... find the difference