(1/2)K X^2
With compression you use a negative X, but get the same answer as stretching by the same amount, because the X is squared.
K is the spring constant, 4.5*10^4.
A spring with a force constant of 4.5×104 N/m is initially at its equilibrium length. How much work must you do to stretch the spring 0.070 m?
How much work must you do to compress it 0.070 m?
5 answers
0.32
Thjn
Study, you must.
K is 4.5 x 10^4 = 45000. Use 0.03 as X