A spring of force constant 120N/m is acted upon by a constant force of 240N.Calculate the elastic potential energy stored in the spring. Please with full solution

Answer 1

Solution:
The elastic potential energy stored in the spring is given by the equation:
U = 1/2 * k * x^2
where k is the force constant and x is the displacement of the spring.

In this case, k = 120N/m and x can be calculated using the equation:
F = k * x
x = F/k
x = 240N/120N/m
x = 2m

Therefore, the elastic potential energy stored in the spring is given by:
U = 1/2 * 120N/m * (2m)^2
U = 480J

Answer 2

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