force=kx
energy=1/2 k x^2=1/2 * k (force/k)^2==1/2 * 75^2/1500 joules one answer is good to two sig digits.
A spring of force constant 1500nm-1 is acted upon by a constant force of 75n.calculate the potential energy stored in the spring (1)1.9j (2)3.2j (3)3.8j (4)5.0j.
6 answers
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That answer is not straight .
This answer is complicated, this is not straight
I don't known whether the answer is correct or not because it is clear