A spring has spring constant 0.3 m/newton. What force is necessary to stretch the spring by 1.5 meters?
F = kx
F = 0.3 x 1.5
F = 0.45
1 answer
The force necessary to stretch the spring by 1.5 meters is 0.45 Newtons.
F = kx
F = 0.3 x 1.5
F = 0.45
1 answer