A spring has spring constant 0.3m /newton. What force is necessary to stretch the spring by 1.5 meters? Use Hooke's Law, F = kx Show all your steps. (4 points)

Answer 1

To find the force necessary to stretch a spring using Hooke's Law, we can use the formula:

$$F=kx$$

where:

• $F$ is the force exerted on the spring (in newtons),
• $k$ is the spring constant (in newtons per meter),
• $x$ is the displacement from the spring's equilibrium position (in meters).

Given:

• $k=0.3,\text{N/m}$
• $x=1.5,\text{m}$

Now, substitute the values into the equation:

1. Substitute $k$ and $x$ into the formula: $$F=(0.3,\text{N/m})\cdot (1.5,\text{m})$$

2. Perform the multiplication: $$F=0.3\times 1.5=0.45,\text{N}$$

Therefore, the force necessary to stretch the spring by 1.5 meters is 0.45 newtons.