A sports car of mass 950 kg (including the driver) crosses the rounded top of a hill (r = 88 m) at 27 m/s.
Determine the normal force exerted by the road on the car. Determine the normal force exerted by the car on the 72-kg driver.
Express your answer using two significant figures.
5 answers
force =mg-mv^2/r where m is 72kg.
Is the equation above used to determine the normal force exerted by the road on the car?
When I used the equation I got (72)(9.8) - (72)(729)/88 = 1.2 (2 sig figs)
This answer was incorrect. What am I doing wrong.
And.... what equation can I use to figure out the 2nd part?
When I used the equation I got (72)(9.8) - (72)(729)/88 = 1.2 (2 sig figs)
This answer was incorrect. What am I doing wrong.
And.... what equation can I use to figure out the 2nd part?
if you haven't already figured it out the equation is for both the driver and car,
a)you pluged in for driver but it should be weight of the car so its
=(950 * 9.8)-(950*729/88)
B)you have already figured out
=(72)(9.8) - (72)(729)/8
C) to determine the speed of the car with no normal force exerted on the driver you simply V= sqrt(91*9.8)
a)you pluged in for driver but it should be weight of the car so its
=(950 * 9.8)-(950*729/88)
B)you have already figured out
=(72)(9.8) - (72)(729)/8
C) to determine the speed of the car with no normal force exerted on the driver you simply V= sqrt(91*9.8)
sorry i made some typing errors
B)=(72 * 9.8) - (72*729/88)
which i got 109 and that = 1.1 *10^2
C)v= sqrt(88*9.8)
the 91 was from my problem i had to do.
hope this helps
B)=(72 * 9.8) - (72*729/88)
which i got 109 and that = 1.1 *10^2
C)v= sqrt(88*9.8)
the 91 was from my problem i had to do.
hope this helps
B=72-9-8