There are a total of 12 sections on the spinner, with 4 sections labeled B and 2 sections labeled D. Therefore, the total number of sections with B or D is 4 + 2 = 6.
The probability of landing on a section labeled B or D is the number of favorable outcomes (6) divided by the total number of possible outcomes (12).
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 6 / 12
Probability = 1/2
Therefore, the probability of landing on sections B or D when spinning the spinner once is 1/2 or 50%.
A spinner is divided into 12 equals sections with three sections labeled a four sections labeled B3 sections labeled C and two sections labeled D if the spinner is spun ones what is the probability of landing on sections B or D?
1 answer
1 answer