A game involves spinning this spinner. What is the probability of the pointer landing on Y?
A circle is divided equally into eight sections.· Two of the sections are labeled with an upper B.
· One of the sections is labeled with an upper G.
· One of the sections is labeled with an upper Y.
· Four of the sections are labeled with an upper R.
· An arrow originating from the center of the circle is pointing at one of the sections with an upper R. (1 point)
one-eighth
one-half
start fraction 5 over 8 end fraction
two-eighths
3 answers
The probability of the pointer landing on Y is 1/8.
The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant the first time and a vowel the second time if the spinner is spun twice.
A circle is divided equally into three sections.· One of the sections is labeled with an upper E.
· One of the sections is labeled with an upper U.
· One of the sections is labeled with an upper N.
· An arrow originating from the center of the circle is pointing at the section labeled with upper U. (1 point)
two-thirds
two-ninths
three-fourths
start fraction 5 over 9 end fraction
A circle is divided equally into three sections.· One of the sections is labeled with an upper E.
· One of the sections is labeled with an upper U.
· One of the sections is labeled with an upper N.
· An arrow originating from the center of the circle is pointing at the section labeled with upper U. (1 point)
two-thirds
two-ninths
three-fourths
start fraction 5 over 9 end fraction
First, we need to find the probability of landing on a consonant on the first spin. Since two out of the three sections are consonants, the probability is 2/3.
Next, we need to find the probability of landing on a vowel on the second spin, given that we landed on a consonant on the first spin. We can represent this with a branch extending from each possible outcome of the first spin:
```
C V
/ | \ / | \
C V N C V N
```
The probability of landing on a vowel, given that we already landed on a consonant, is 1/2 since there is one vowel and one consonant remaining.
To find the overall probability of landing on a consonant and then a vowel, we multiply the probabilities of each event:
(2/3) x (1/2) = 1/3
Therefore, the probability of the spinner landing on a consonant the first time and a vowel the second time is 1/3.
Next, we need to find the probability of landing on a vowel on the second spin, given that we landed on a consonant on the first spin. We can represent this with a branch extending from each possible outcome of the first spin:
```
C V
/ | \ / | \
C V N C V N
```
The probability of landing on a vowel, given that we already landed on a consonant, is 1/2 since there is one vowel and one consonant remaining.
To find the overall probability of landing on a consonant and then a vowel, we multiply the probabilities of each event:
(2/3) x (1/2) = 1/3
Therefore, the probability of the spinner landing on a consonant the first time and a vowel the second time is 1/3.
31 answers