A sphere of mass 500g moving with a velocity of 200 cm s-1collides centrally with another sphere of mass 100 g moving with a velocity of 100 cm s-1towards it. After the collision the two spheres stick together. Find the final velocities of the two spheres and the loss in kinetic energy of the system.

Question

Plz answer fast

Answer 1

use meters and kilograms or I get confused
original momentum = 0.5 * 0.2 - 0.1 * 0.1= 0.09 kg m/s
final momentum = 0.6*v
final momentum = original so
0.6 v = 0.09
v = 0.15 m/s
original ke = (1/2)[0.5*(0.2)^2 + 0.1(0.1)^2] = .5[.02+.001]
= 0.0105 Joules
final ke =.5[0.6 *(0.15)^2] = 0.00675 Joules
subtract them

Answer 2

Given: M1 = 0.5 kg, V1 = 2 m/s.
M2 = 0.1kg, V2 = 1m/s.
V3 = Velocity 0f M1 and M2 after collision.

Momentum bef0re = Momentum after.
M1*V1+M2*V2 = M1*V3+M2*V3
0.5*2+0.1*(-1) = 0.5V3+0.1V3
0.6V3 = 0.9
V3 = 1.5 m/s.

KEb = 0.5M1*V1^2+0.5M2*V2^2 = 0.25*2^2+0.05*(-1)^2 = 1.05 Joules.
KEa = 0.5M1*V3^2+0.5M2*V3^2 = 0.25*1.5^2+0.05*1.5^2 = 0.675 Joules.
KE lost = KEb-KEa =