A speeder traveling at 41 m/s passes a motorcycle policeman at rest at the side of the road. The policeman accelerates at 3.3 m/s2. To the nearest tenth of a second how long does it take the policeman to catch the speeder?

Answer 1

Write equations for the distance travelled by speeder and policemen after the speeder passes.

Set them equal and solve for t.

Answer 2

Im sorry I am new to physics this is my first year and I still have no idea what to do for this problem. The other two that you answered I had them correct before you answered them and was using it as a check. When I reworked them your way, I got the same answer. However on this problem, I am at a loss because I feel there is not enough data, and I am obviously wrong. I worked it differently than u said and got 12.4 seconds, which sounds wrong. Please help!