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A speeder passes a parked police car at a

constant speed of 31.8 m/s. At that instant,
the police car starts from rest with a uniform
acceleration of 2.74 m/s
2
.
How much time passes before the speeder
is overtaken by the police car?

1 answer

vt= at²/2
t=2v/a=2•31.2/2.74= 22.8 s
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