the distance traveled is the same, in the same time.
dspeeder=20.1*t
dscop=1/2 *2.65 t^2
set them equal, and solve for time t.
A speeder passes a parked police car at a
constant speed of 20.1 m/s. At that instant,
the police car starts from rest with a uniform
acceleration of 2.65 m/s
2
.
How much time passes before the speeder
is overtaken by the police car?
Answer in units of s.
1 answer