A speed skater moving across frictionless ice at 9.0 m/s hits a 5.3 m -wide patch of rough ice. She slows steadily, then continues on at 5.8 m/s. What is her acceleration on the rough ice? Express your answer using two significant figures.

Answer 1

V^2 = Vo^2 + 2a*d.

V = 5.8 m/s.
Vo = 9.0 m/s.
d = 5.3 m.
Solve for a. It will be negative.

Answer 2

-0.302