5.7 = 8t + 1/2 at^2
6.5 = 8 + at
a = -1.9079 m/s^2
t = 0.7862 s
A speed skater moving across frictionless ice at 8.0 m/s hits a 5.7m-wide patch of rough ice. She slows steadily, then continues on at 6.5m/s.
What is her acceleration on the rough ice?
1 answer
1 answer