9.9 = v^2/r
9.9 * 100 = v^2
v = 99.5 m/s
Time for revolution = 2 pi r/v
= 2 pi * 100/99.5 = 6.31 seconds = .105 minutes
1/.105 = 9.5 revs/minute
A space station in the form of a large wheel, 200m in diameter, rotates to provide an "artificial gravity" of 9.9m/s^2 for people located at the outer rim. What is the frequency of the rotational motion for the wheel to produce this effect? Answer in units of rev/min.
frequency equals wavelength/velocity right? So how do I solve this question?
acceleration= angularvelocity^2*radius
where angular velocity is in units of radians/sec.
Solve for angular velocity above, then convert to revs/min
Note ( one rev= 2PI radian, and 1Min=50 sec.
A revolutionary cannon, with a mass of 2000kg, fires a 20kg ball horizontally. The cannonball has a speed of 140m/s after it has left the barrel. The cannon carriage is on a flat platform and is free to roll horizontally. What is the speed of the cannon immediately after it was fired? Answer in units of m/s.
Massbullet*velcity bullet= masscannon*veloicty cannon
solve for velocity of the cannon
1 answer