A space station, in the form of a wheel 197 m in diameter, rotates to provide an “artificial gravity” of 2.5 m/s2 for persons who walk around on the inner wall of the outer rim. The rate of the wheel’s rotation in revolutions per minute that will produce this effect is

Question

rev/min
My online course is telling me the answer is 1.52, but I can't get this answer no matter how I try.*
*actually its telling me v=1.52, but I believe this to still be rpm
Most recent work
a=v^2/r 2.5=v^2/197

v=Sqrt(2.5*197)

v=22.19234102

Circumfrence= 2*pi*r c=2*pi*197

c=1237.787506

c/v=55.77543641 seconds

s/(1 min=60 seconds)

55.77543641/60= 0.929590607 minuets

1/0.929590607= 1.075742367 rev/min

I don't see where my math has gone wrong.

Thank you

Answer 1

radius is half the diameter