Question

A space station, in the form of a wheel 197 m in diameter, rotates to provide an “artificial gravity” of 2.5 m/s2 for persons who walk around on the inner wall of the outer rim. The rate of the wheel’s rotation in revolutions per minute that will produce this effect is
rev/min
My online course is telling me the answer is 1.52, but I can't get this answer no matter how I try.*
*actually its telling me v=1.52, but I believe this to still be rpm
Most recent work
a=v^2/r 2.5=v^2/197

v=Sqrt(2.5*197)

v=22.19234102

Circumfrence= 2*pi*r c=2*pi*197

c=1237.787506

c/v=55.77543641 seconds

s/(1 min=60 seconds)

55.77543641/60= 0.929590607 minuets

1/0.929590607= 1.075742367 rev/min

I don't see where my math has gone wrong.

Thank you

Answer 1

radius is half the diameter