My answer:
A. A=29
B. B > 29
a. Solve a – 9 = 20
b. Solve b – 9 > 20
c. How is solving the equation in part a similar to solving the inequality in part b?
d. How are the solutions different?
9 answers
add 0 to both sides in both cases.
the only difference I see is one is an equality with one solution and one is an inequality with multiple solutions
the only difference I see is one is an equality with one solution and one is an inequality with multiple solutions
I mean add 9 to both sides :)
Ok im putting my grades in your hands :)
im confused
wats the answer ;-;
1.
Inequality : 5 - 1.5
Solved : 5 < with line under the inequality 3.5
2 .
A: is " a = 29 "
B: is " b > 29"
How I solved it, ^^ You just add 9 + 20.
Im not including question d. Figure it out yourself. ♥🤒
Inequality definiton: < > _< _>
Inequality : 5 - 1.5
Solved : 5 < with line under the inequality 3.5
2 .
A: is " a = 29 "
B: is " b > 29"
How I solved it, ^^ You just add 9 + 20.
Im not including question d. Figure it out yourself. ♥🤒
Inequality definiton: < > _< _>
here you guys go :D
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Solve
a
–
9
=
20
Solve
b
–
9
>
20
How is solving the equation in part a similar to solving the inequality in part b?
How are the solutions different?
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Solve
a
–
9
=
20
Solve
b
–
9
>
20
How is solving the equation in part a similar to solving the inequality in part b?
How are the solutions different?
sorry it didn't work earlier.
A) The value of a is 29.
B) The value of b is greater than 29.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,
We have to solve for a.
By using addition property of equality, we will add both side by 9;
Hence the value of a is 29.
Solving for Part B.
Given,
We have to solve for b.
By using addition property of inequality, we will add both side by 9;
Hence the value of b is greater than 29.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
A) The value of a is 29.
B) The value of b is greater than 29.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,
We have to solve for a.
By using addition property of equality, we will add both side by 9;
Hence the value of a is 29.
Solving for Part B.
Given,
We have to solve for b.
By using addition property of inequality, we will add both side by 9;
Hence the value of b is greater than 29.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
1 answer