A solution is prepared by dissolving 130 g of NaNO3 in 100 g of water at 80°C. The solution is cooled to 0°C. How many grams of compound remain in solution?

Question

How many grams of solid are formed?

Answer 1

This is pretty easy. WAht is the saturated level (mass NaOH3 per 100gwater). Look at the solubility curves to get that.
http://www.goldrecovery.us/images/solgraph.jpg

Then, that point tells you how much is still in solution.

The difference is how much precipated.

Answer 2

do i find out what the saturated level is for 80C or 0C

Answer 3

The molarity of urea in a solution prepared by dissolving 16 g of urea (MW = 60.0 g/mol) in 39g of H2O is M. The density of the .solution is 1.3 g/mL 0.11 .a O 6.3 .b O 3.7 .C O 6.8 .d o 0.16 .e O