Ask a New Question

What is the boiling point elevation of a solution of NaNO3 (85.0 g/mol, complete dissociation) made by dissolving 10.0 g of NaNO3 into 200 g of water (Kb = 0.512◦C/m)?

1 answer

delta T = i*Kb*m
i = 2 for NaNO3
Kb is given
m = mols/Kg. Kg is 0.2
mols = grams/molar mass NaNO3.

Ask a New Question or answer this question.

Similar Questions

which solution has the highest boiling point?a. 1 mole of NaNO3 in 500 g of water b. 1mole of NaNO3 in 1000g of water c. 1mole
1. 1 answer
A solution was made by dissolving3.75g of a pure non-volatile solute in 95g ofacetone. The boiling point of pure acetone was
1. 0 answers
A solution was made by dissolving 3.75 g of a pure non volatile solute in 95 g of acetone. The boiling point of pure acetone was
1. 2 answers
a solutiona solution is made by dissolving 3.75g of a pure nonvolatile solute in 95g of acetone. the boiling point of pure
1. 0 answers

more similar questions