molarity=molestolulent/volume solution
volume solution=.150+.020
Moles toulene=20*.0867g/ml*molmass
molarity=molestoluene/kg solvent
kgsolvent=150*.0874 kg
I am wondering what was the problem on this?
A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 150.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are
____M and
_____m.
1 answer
1 answer