A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

Answer 1

Molarity=molestoluene/volumesolutioninliters

molality= molestoulene/(kg benezene)

Do you have any questions on how to do these?

Answer 2

how do you get the volume of the solution

Answer 3

and how do you get moles of toluene? please