A solution contains 2 mEq/ml of KCL (Molecular weight 74.5). If a 20 ml ampule of this solution is diluted to 1 liter what is the percent strength of the resulting solution?

Answer 1

2 mEq/mL x (20 mL/1000 mL) = 0.040 mEq/mL or 4.0 mEq/100 mL.
How many grams do you have in 4.0 mEq? That's 4.0 mEq x mEq wt = 4.0 x 0.0745 = about 0.003g/100 which makes it about 0.003% (and that's percent w/v).

Answer 2

0.039