Assume 1000ml of the solution.
total mass=1000ml/density=1100g
moles of glycerol=550/molmassgly /1L=550/92.1= not your answer.
A solution containing equal masses of glycerol, C3H8O3, and water has a density of 1.10 g/mL. Calculate the molality of glycerol.
I got 11.9 m.
2 answers
Step 1:
Make the assumption that glycerol and water has 50g since they have equal masses
Step 2:
Convert grams of glycerol to moles. If you don't know how to do that then I'd quit chem right now...
moles of C3H8O3=.543
Step 3:
convert the 50g of water into kg.
kg water= .05
Step 4:
Set up molality equation:
(.543)/(.05)= 10.9m
Answer: 10.9m
Make the assumption that glycerol and water has 50g since they have equal masses
Step 2:
Convert grams of glycerol to moles. If you don't know how to do that then I'd quit chem right now...
moles of C3H8O3=.543
Step 3:
convert the 50g of water into kg.
kg water= .05
Step 4:
Set up molality equation:
(.543)/(.05)= 10.9m
Answer: 10.9m