A solution containing 7.00grm of lead nitrate is combined with a solution containing 7.00g of sodium sulfate.

Question

(a) write a balance equation for the reaction. Pb(no3)2 aq + NaSo4 aq ---> PbSo4 +2 NaNo3. I think that's right.
(b)How many moles of the the product are formed? Is the product PbSo4 , 2NaNo3 or both?
Confused.

Answer 1

Pb(no3)2 aq + NaSo4 aq ---> PbSo4 +2 NaNo3. I think that's right.
except that o is oxygen. n isn't nitrogen. Sodium sulfate is Na2SO4.

1. Convert 7.00 g Pb(NO3)2 to moles. moles = grams/molar mass.
2. Convert 7.00 g Na2SO4 to moles. Same procedure.
3a. Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles PbSO4.
3b. Same procedure, convert moles Na2SO4 to moles PbSO4.
3c. Likely, the answers from 3a and 3b will be different which means one of them is wrong. The correct moles PbSO4 formed is ALWAYS the smaller value.

4. The question doesn't ask for grams PbSO4, but you can convert the smaller value in 3c to grams. g = moles x molar mass.

The ppt is PbSO4 because it is insoluble. NaNO3 is soluble and if filtered can be separated from the solid PbSO4.