a solution containing 100g of unknown liquid and 900g water has a freezing point pf -3.33 C. given kf=1.86 degrees c for water, the moelcular weight of the unknown liquid is what?

Question

a solution containing 100g of unknown liquid and 900g water has a freezing point pf -3.33 C. given kf=1.86  degrees c for water, the moelcular weight of the unknown liquid is what?

DrBob222 · Answer

delta T = Kf*molality Solve for m m = #moles/kg solvent Substitute m and kg solvent, solve for # moles. # moles = grams/molar mass You have #moles and grams, solve for molar mass.