a solid aluminum ingot weighs 89N in air a)what is the volume b)the ingot is suspended from a rope and totally immersed in water. what is the tension in the rope(the apparent weight of the ingot in water)?

Answer 1

mass = W/g = 9.08 kg

(a) For the volume, divide the above mass by the density of aluminum, which you should look up.

(b) Apparent weight = Actual weight - buoyancy

= 89 N - (Volume)*(water density)*(g)