A solid aluminum ingot weighs 88.0 N in air.What is its volume?The ingot is suspended from a rope and totally immersed in water. What is the tension in the rope (the apparent weight of the ingot in water)?

To find the volume would i do density/specific gravity of aluminum?

1 answer

For the volume, divide the mass (88.0 /9.81 = 8.97 kg or 8970 g) by the density of aluminum, which you should look up. Make sure you use units of

Use the volume to compute the buoyant force when totally submerged.

The weight MINUS the buoyant force will equal the cable tension.