Isn't there a standard formula for this? All you have to really calculate is the turns. I think that will be close to 1.5/.0028
check my thinking.
A solenoid is wound with a single layer of insulated copper wire of diameter 2.800 mm and has a diameter 5.000 cm and is 1.500 m long. Assume that the adjacent wires touch and that the insulation thickness is negligible. what is the inductance per meter(H/m) for the solenoid near its center.
4 answers
This is a two part question the first part was to find the number of turns which is 535 like you said.
L=(mewsub0*N^2*A)/length
A= .5 pi r^2
N=number of turns=535
mewsubO= 4 pi 10^-7
thats the formula to use but I'm not getting a correct answer any suggestions?
L=(mewsub0*N^2*A)/length
A= .5 pi r^2
N=number of turns=535
mewsubO= 4 pi 10^-7
thats the formula to use but I'm not getting a correct answer any suggestions?
How can area be 1/2 PI r^2? That is not what I memorzed in the sixth grade.
haha thanks bobpursley you are right that's the problem
0 answers